* 1*2^6+1*2^5+0*2^4+0*2^3+1*2^2+0*2^1+0*2^0 int mod = binary%10;//1100100%10=0,110010%10=0,11001%10=1,1100%10=0,110%10=0,11%10=1,1%10=1 decimal = decimal+(mod*(int ...

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Abstract: Binary floating-point numbers with finite precision cannot represent all decimal numbers with complete accuracy. This can often lead to errors while performing calculations involving ...