SOLVED: Case I: Uniform beam under distributed load:In the shown figure, a uniform beam is subject to a linearly increasing distributed load. The deflection y (m) can be expressed by the equation:Wo y = (αx^5 212x^3 Ltx) / 120EILWhere:- Wo is the distributed load (kN/cm)- E is the modulus of elasticity- I is the moment of inertia (m^4)- L is the length of the beamTo find the requirements, we will use the following parameters:- L = 600 cm- E = 50,000 kN/cm^2- I = 30,000 cm^4- Wo = 2.5 kN/cm(r
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SOLVED: Case I: Uniform beam under distributed load:In the shown figure, a uniform beam is subject to a linearly increasing distributed load. The deflection y (m) can be
SOLVED: Case I: Uniform beam under distributed load:In the shown figure ...
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